A Level Maths Notes: FP4 – Invariant Points
Any transformation
represented
by a matrix
whose
entries are numbers is linear. The matrix will send a line to a line.
Sometimes it may send points on a line to some other point on the
same line, and sometimes it will send a point to itself. In the
second case, the point is said to be invariant.
Every transformation represented by a matrix has at
least one invariant point – the origin, since if
is the matrix representing T,
where
indicates
the zero vector with every entry equal to 0. Suppose that
is
an invariant of
so
that![]()
The above equation means that
is
an eigenvector of
with
eigenvalue 1. Not all matrices have such eigenvalues, so this is a
condition of a transformation having invariant points other than vec
0 . If such a vector
exists,
any scalar multiple of
will
also be invariant since![]()
This means that the eigenvector corresponding to an eigenvalue of 1 will define a line every point of which is an invariant point.
Example:
Suppose a transformation
is
represented by
The
eigenvalues are the solutions to
![]()
![]()
![]()
If
the
eigenvectors
are
the solutions to![]()
![]()
Hence
and
an eigenvector is
but
this is not invariant, because the eigenvalue is 3 so![]()
If
the
eigenvectors
are
the solutions to![]()
![]()
Hence
and
an eigenvector is
but
this is invariant, because the eigenvalue is 1 so![]()
Also, any scalar multiple of
is
invariant so in particular
which
defines the line
is
invariant.