O Level Additional Maths Notes: Solving Quadratic Exponential Equations by Substitution
Some exponential equations can be factorised in linear factors. The simplest can be factorised into quadratic equations. We then put each factor equal to zero and solve it.
Example: Solve
(1)
Factorise to get![]()
or![]()
The above equation has two
solutions. In general, as for quadratic equations, an exponential
which can be expressed as two factors can have one, two or no
solutions. It is convenient to make clear the connection by
expressing the original equation as a quadratic using the
substitution
Then
and
equation (1) above becomes
This
equation factorises to give
so
Since
the original equation was expressed in terms of
we
still have to find
but
we can use the substitution
with
the values of
that
we have found, to find![]()
or![]()
Example: Solve![]()
Substitute
to
get
and
factorise this expression to give![]()
This
has no solution since there is no real log of a negative number.
![]()
Example: Solve![]()
Substitute
to
get
and
factorise this expression to give![]()
This
has no solution since there is no real log of a negative number.
This
has no solution since there is no real log of a negative number hence
the equation has no solutions.