University Maths Notes: Calculus – The Equality of Mixed Partial Derivatives
Suppose that
is
a function of
and
with
partial derivatives
and
These
are again functions of
and
and
may themselves possess partial derivatives:
![]()
![]()
and![]()
The middle two terms are called the second order partials. There
are two mixed partials -
and
The
first is obtained by differentiating
first
with respect to
then
and
the second is obtained by differentiating first with respect to
then![]()
For many functions
In
fact if
and
it;s partials
and
are
all continuous on a set
then
on![]()
If
is
a function of three variables
then
there are three first partials
and
and
nine second partials:![]()
and
![]()
Again the second partials are equal:
![]()
and![]()
provided that
and
all it's first and second partial derivatives are continuous.
Example:![]()
![]()
![]()
![]()
Hence![]()