Apparatus:
Dynamics trolley, tape measure (or 2 x metre rulers), stop-clock, corridor
Diagram:

Procedure:
1. Gently push the trolley away from a known position on the corridor carpet so that it stops after about one metre.
2. Repeat the above but this time use the stop-watch to time, time
how long it takes the trolley to stop and measure how far the trolley travels, the stopping distance
(to the nearest centimetre).
3. Repeat stages 1 & 2 for approximate stopping distances of 25cm, 50cm, 75cm, 1.5m & 2m.
4. Measure the mass,
of the trolley.
5. Calculate time squared
for each of your measurements, then tabulate your results.
6. Draw a graph of stopping distance against time squared.
For a constant frictional force,
the graph is expected to be a straight line through the origin.
(Do not worry if you in fact obtain a curve that does not pass through the origin!)
7. Calculate the gradient,
of your graph.
(Note: If you have drawn a curve then calculate the gradient of the tangent to your curve for a stopping distance of 1 metre.)
8. According to theory the work done by a constant retarding frictional force
applied for a distance
is equal to the initial kinetic energy of the trolley,
i.e.
Also if the trolley's deceleration is uniform then
(
)
Combining the above two equations yields![]()
9. The gradient,
of your graph should therefore be equal to![]()
Use your gradient value to calculate the value of the retarding force![]()
10. Use the above calculations and your graph to find for a stopping distance of 1m:
(a) the stopping time
(b) the initial velocity
(c) the power needed to maintain this velocity by a motor mounted on the trolley.
(you need to use the relation: power = force x velocity here)
(d) Explain why the power actually needed by the motor would in fact be substantially higher than that above.