Theorem
Suppose
is a space such that
where
and
are nonempty, open subsets of![]()
If
is any connected subset of
then either
or![]()
Proof
Suppose
with
and that
and![]()

Then
are nonempty, disjoint, subsets of
open in
and![]()
Hence
is not connected and either
or
hence either
or![]()