Theorem
If a topological space
is a T1 space then for any pair of distinct points
open sets
exist with![]()
![]()
![]()
![]()

Proof
Suppose
is a T1 space. For any![]()
is closed. Let
be distinct points of![]()
and
are closed so
and
are open.
Also
and![]()
and![]()
Conversely suppose![]()
is open. Let
then
and an open set
exists such that
Hence
and ![]()
Since all
are open
is open and
is closed so![]()