Theorem
If a topological space
is second countable it is separable.
Proof
Suppose
is a second countable space. Then there exists a countable base
of
For each
choose
such that![]()
The set
is countable. Let
and let
be an open set containing
At least one set
exists such that![]()

Since
and![]()
Hence
is an accumulation point of
since every open set containing
also contains a point of
different from![]()