Theorem
If
is a basis of a topology
then the topology
is unique.
Proof
Let
represent any set and let
represent a collection of subsets of
Suppose
is a basis for distinct topologies
and![]()
Since
and
are distinct, at least one subset
exists such that
but
or vice versa. Since also
is a basis for
and
where ![]()
Since
is a basis for
any union of elements of
must be a member of![]()
This is a contradiction since
and
are distinct, hence
and a basis determines a unique topology.