Theorem
If
are compact subsets of a topological space
then their union
is also compact.
Proof
Let
be compact subsets of
and let
be an open cover of
so that
Since
is compact a finite subcover
exists for![]()
Then
and
is compact.
Theorem
If
are compact subsets of a topological space
then their union
is also compact.
Proof
Let
be compact subsets of
and let
be an open cover of
so that
Since
is compact a finite subcover
exists for![]()
Then
and
is compact.