Theorem
Let
be a class of non empty connected subsets of
with non empty intersection so that![]()
Then
is path connected.
Proof
Let
Path connected subsets of
exist such that![]()
The non empty intersection
contains at least one point, say![]()
Then
so there is a path
in
from
to
with
and
so there is a path
in
from
to
with![]()
Define
by

Then
is a path from
to
and
is connected.