Theorem
A path connected space is always connected. The converse is not true. That is,
is a connected space does not imply it is connected.
Proof
Let
and
be subsets of![]()
![]()
![]()
is a closed interval and
is a continuous image of a closed interval. Hence both are connected. Each point of
is an accumulation point of
hence
and B are not separated.
Hence
is connected.
But
is not path connected. There is no path connecting any point of
with any point of
since
and
have no points in common.
Hence connected does not imply path connected.