Theorem
Each element of a topological space
is contained in some component of![]()
Proof
Obviously each element of
is contained in at least one connected subset of![]()
Let
be the family of all connected subsets of
containing![]()

is connected for each![]()
is connected and contains![]()
This union is also unique, since every connected subset of
containing
is included and non are excluded.
Hence
is a maximally connected subset of
containing
so must be a component of![]()