Theorem
Every Cauchy sequence
in a metric space
is bounded and totally bounded.
Proof
Let
be a Cauchy sequence in a metric space![]()
A subset
of a metric space
is totally bounded if
has an
- net for every
(an
- net for
is a finite set of points
such that for every
there is
such that
).
Let
Since
is Cauchy, there exists
such that![]()
Hence the diameter of the set
is at most
The
- net for the sequence
is then![]()