Theorem
If
is a subset of a second countable space
then overy open cover of
is reducible to a finite cover.
Proof
Let
be a countable base for
and let
be an open cover of
so that![]()
For each![]()
exists such that![]()

Thus![]()
The family of sets
is a subset of
hence hence it is countable so
where
is a subset of
For each
we can choose
such that![]()
Hence
and
is a countable subcover of![]()