Theorem
Ifis a subset of a second countable space
then overy open cover of
is reducible to a finite cover.
Proof
Letbe a countable base for
and let
be an open cover of
so that
For eachexists such that
Thus
The family of setsis a subset of
hence hence it is countable so
where
is a subset of
For each
we can choose
such that
Henceand
is a countable subcover of