Theorem
If
is a separable metric space it is second countable.
Proof
Let
be a separable metric space. Let A be a countable dense subset of
so![]()
Let
be the set of all open balls with centres in
and with rational radii:
![]()
and
are countable sets, hence so is![]()
Take
where
is open in
There is an open ball
such that![]()

Since
is dense in
we can find
such that
Let
be a rational number satisfying
Then![]()
Since
and
is countable,
is a countable base for the given topology on![]()