Theorem
The statements
is a closed function and![]()
are equivalent.
Proof
Suppose
is a closed function. Let
represent any subset of
then
is a closed set and
is closed.
Since
for all
we have![]()
Suppose now that for each set![]()
![]()
If
is a closed set then
and![]()
Therefore
so
is closed and
is a closed function.