Theorem
If
is one to one and onto,
is continuous and
is a T2 space, then
is a T2 space.
Proof
Let
and
represent any two points of
If
is one to one and onto, two distinct points x_1 , x_2 in X exist such tha
and![]()
is a Hausdorff space so there are open sets
and
such that![]()
Since f is bijective,![]()
Since
is continuous the function
maps open sets into open sets. Hence
are open sets and![]()
Hence
is a T2 space.