Theorem
The Alexandroff compactification of a space
is T2 if and only if it is T2 and
is locally compact.
Proof
Suppose
is compact, then the Alexandroff compactification of
is![]()
If
is T2, it is also locally compact.
Suppose
is not compact and
is the Alexandroff compactification of
If
is T2 then so is
since
is a subspace of![]()
Since
is T2 and compact,
is also locally compact. Let
with
If
then
and
exist such that
because
is T2.
Suppose
is an ideal point then
and a compact subset B of
exists such that![]()
Hence
is a neighbourhood of![]()
is a neighbourhood of
and![]()
Hence
is T2.