A particle travelling on the inside surface of a smooth sphere will just leave the surface when the reaction between the particle and the inner surface is zero.
Suppose a particle of massat the bottom A of a sphere of radius r is given a horizontal speed
It will move along the internal surface of the sphere. Suppose at some point B it has a speed
If the line from the centre of the circle to the point B makes an anglewith the upwards vertical then the force of gravity will have a component
towards the centre of the circle.
Applyingtowards the centre of the circle gives
(1)
Since the inside of the sphere is smooth, no work is done against friction, and energy is conserved in going from A to B. The potential energy at B is
Hence
Cancellinggives
(2)
Putin equation (1) and cancel
from both sides, obtaining
then
Substitute this into (2) to obtain
Rearranging this formula forgives
Sincewe must have
Obviously
The particle will leave the inside surface at some point ifThis corresponds to the particle not having enough initial kinetic energy to reach the top of the sphere.