Integrating arccos x Print To evaluate \[\int^1_0 cos^{-1} xdx\] consider the following graph.The area under the curve of \[y=cosx\] is adjacent to both \[x\] and \[y\] axes so \[\int^1_0 cos^{-1} y dy= \int^{\pi /2}_0 cosx dx= [sinx]^{\pi /2}_0 =1\]. Prev Next Add comment Name (required) E-mail (required, but will not display) Refresh SendCancel