\[f(x)=0\]
has solutions \[x=-3, \; 1, \; 2\]
.The function is then transformed to become
\[f(3x-2)\]
. What will be the solutions of the equation \[f(3x-2)=0\]
?The function actually tells us that
\[f(-3)=f(1)=f(2)=0\]
. We should be solving\[f(3x-2)=f(-3) \rightarrow 3x-2=-3 \rightarrow 3x=2-3=-1 \rightarrow x =- \frac{1}{3}\]
\[f(3x-2)=f(1) \rightarrow 3x-2=1 \rightarrow 3x=2+1=3 \rightarrow x =1\]
\[f(3x-2)=f(2) \rightarrow 3x-2=2 \rightarrow 3x=2+4=4 \rightarrow x = \frac{4}{3}\]