## Area of Blocks Problem

Suppose we have the arrangement of identical blocks below. What is the area of the arrangement?

If we label the shorter side
$x$
and the longer side
$y$
then we can add the labels as showm.

We get the simultaneous equations
$x+y=7$
(1_
$x+2y=11$
(2)
(2)-(1) gives us
$y=4$
then using (1)
$x+4=7 \rightarrow x=3$
.
The area of the arrangement is then
$4 \times 3 \times 4=48$
.