Suppose we want to find all the integers satisfying![]()
is a difference of squares and factorises as
and 7 factorises as
or
so
or
or
or
We may equate factors on either side to give either
and
or
and![]()
The first of these gives the simultaneous equations
![]()
![]()
The solution is
and![]()
The second of these gives the simultaneous equation
![]()
![]()
The solution is![]()
The first of these gives the simultaneous equations
![]()
![]()
The solution is
and![]()
The first of these gives the simultaneous equations
![]()
![]()
The solution is
and![]()
If
and
is not a prime number, a great many solutions exist since m+n and m-n must be matched with each factor in turn, either both negative or positive.