Theorem
The product of the lengths of chords of a circle with the extended chords that intersect outside a circle are equal.

![]()
Proof
Draw the chords
and![]()

Angle
is common to triangles
and![]()
Angles
and
are the same, since both are subtended by the points
and
on the circumference.
Hence angles
and
are the same so that triangles
and
are similar.
Hence![]()