Suppose that
and
are functions continuously differentiable on a region
As
ranges over
the point
generates a region
in the
plane.

If the mapping
is one to one on the interior of
and the Jacobian
on the interior of B then the area of![]()
Suppose then that we want to integrate some continuous function
over
If the integral is intractable then we can change variables to
and integrate over
instead, because
![]()
Proof: Break up
into
smaller regions
We can write
![]()
![]()
![]()
![]()
The last expression is a Riemann sum for
and the expression tends to this integral as the diameter of the
tends to zero.