Taylor Series of a Polynomial Returns the Polynomial

A Taylor series of a polynomial  
\[P(x)\]
  of finite degree always returns the polynomial  
\[P(x)\]
.
Example:  
\[P(x)=x^2\]
  as a Taylor series at  
\[x=1\]
.
\[\frac{d (P(x))}{dx}=2x, \; \frac{d^2 (P(x))}{dx^2}=2 \]
  and higher derivatives all equal 0.
The Taylor series is
\[\begin{equation} \begin{aligned} T(x) &= P(1)+ \frac{d(P(x))}{dx}|_{x=1}(x-1)+ \frac{1}{2!} \frac{d^2(P(x))}{dx^2}|_{x=1}(x-1)^2 \\ &= 1 + 2(x-1)+ (x-1)^2 \\ &= 1+2x-2+x^2-2x+1 \\ &= x^2 \end{aligned} \end{equation}\]
.
This is because a polynomial is uniquely determined by it's coefficients, so if  
\[P(x_= \sum a_nx^n = \sum b_n x^n\]
  then  
\[a_n=b_n\]
  for all  
\[n\]
.

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