## Consecutive Composite Numbers

\[(n+1)!+2, \; (n+1)!+3, \; (n+1)!+4,..., \; (n+1)!+(n+1)\]

Each of these numbers is composite, divisible by 2, 3, 4,...,n+1 respectively and as

\[n \rightarrow \infty\]

so does the leg nth of consecutive numbers. Call Us 07766496223

\[(n+1)!+2, \; (n+1)!+3, \; (n+1)!+4,..., \; (n+1)!+(n+1)\]

Each of these numbers is composite, divisible by 2, 3, 4,...,n+1 respectively and as

\[n \rightarrow \infty\]

so does the leg nth of consecutive numbers.