Theorem
A topological space
is normal if and only if, for every closed set
and every open set
containing
an open set
exists such that![]()

Proof
Let
be a normal space. Let
be a closed set and
an open set in
with![]()
is closed and![]()
and
are disjoint closed sets hence open sets
and
exist such that
and![]()
Since
we have
and since
we have![]()
The set
is closed hence![]()
Now let
and
be disjoint closed sets then
and
is open. An open set exists such that![]()
Since
we have
Also since
we have![]()
Since
is open,
and
where
and
are open sets.