Theorem
If
is a basis for a a topological space
and
is a basis for a a topological space
then
is a basis for a the topological space![]()
Proof
Suppose
is open. Then
is the union of cartesian products
where
and
are open in![]()
respectively hence![]()
is a basis of
and
is a basis for
so for each
and
where![]()
Hence![]()
The set
is the required basis for![]()