Theorem
 A closed subset of a countably compact space
of a countably compact space is countably compact.
is countably compact.
Proof
Let be a countably compact set and let
be a countably compact set and let be a closed subset of
be a closed subset of
Let be an infinite subset of
be an infinite subset of A is also an infinite subset of a countably compact space
A is also an infinite subset of a countably compact space An accumulation point
An accumulation point of
of exists such that
exists such that

Since
 is also an accumulation point of
is also an accumulation point of Since
Since is closed, it contains all it's accumulation points, so
is closed, it contains all it's accumulation points, so Hence an infinite subset
Hence an infinite subset of a closed subset
of a closed subset has an accumulation point
has an accumulation point hence
hence is countably compact.
is countably compact.