Theorem
A closed subsetof a countably compact spaceis countably compact.
Proof
Letbe a countably compact set and letbe a closed subset of
Letbe an infinite subset ofA is also an infinite subset of a countably compact spaceAn accumulation pointofexists such that
Sinceis also an accumulation point ofSinceis closed, it contains all it's accumulation points, soHence an infinite subsetof a closed subsethas an accumulation pointhenceis countably compact.