Theorem
A closed subsetof a countably compact space
is countably compact.
Proof
Letbe a countably compact set and let
be a closed subset of
Letbe an infinite subset of
A is also an infinite subset of a countably compact space
An accumulation point
of
exists such that
Sinceis also an accumulation point of
Since
is closed, it contains all it's accumulation points, so
Hence an infinite subset
of a closed subset
has an accumulation point
hence
is countably compact.