Theorem
A set with the order topology is a T2 space.
Proof
Suppose
is an ordered set and let
represent the family of subsets of
of the form
or
for![]()
The family
is a subbasis for a topology
on
called the order topology on
induced by![]()
Let
represent distinct points. Since
is ordered, either
or
Suppose
then there are two possibilities.
1. An element
exists such that![]()
Then
and
are disjoint neighbourhoods of
and
respectively.
2. No
exists such that
then
and
are disjoint neighbourhoods of
and
respectively.