Theorem
Letwith the indiscrete topology is not a T0 space.
Proof
A spaceis a T0 space if for any two distinct elements
there is an open neighbourhood of one which does not contain the other.
With the indiscrete topologywe cannot separate 0 from 1 or 1 from 0 hence
is not a T0 space.
Consider the setwith the topology
For the distinct points 0 and 1, an open set
exists such that
but
hence
is a T0 space.
Each metric space is a T0 space since for distinct pointsand
there exists
such that
hence
but