Theorem
Let
and
be disjoint compact subsets of a Hausdorff space
Open sets
and
exist such that
and![]()
Proof
Let
Since![]()
is compact so open sets
and
exist such that
and
(1)
The family of open sets
forms an open cover of the compact set
so a finite subcover
exists. For each
we can find a corresponding
satisfying (1).
Let
and![]()
Then
and
and both
and
are open.
For each![]()
hence![]()