Theorem
Any Topological Space With the Indiscrete Topology Containing More Than One Point is Normal
Proof
Any topological space with the indiscrete topology containing more than one point is normal
Proof
A topological space
is normal if, given any two disjoint subsets
and
of
there are disjoint open sets
and
such that
and![]()
The indiscrete topology
consists of sets
and![]()
Hence the only closed sets are
and
because
and![]()
Hence there are no non empty disjoint closed subsets of
The space is normal.