Theorem
If
are homotopic mappings taking values in the space
and
are defined on
and homotopic, then the mappings
and
are homotopic.
Proof
Let
so that
is homotopic to![]()
A continuous function
for all
exists such that![]()
Let
so that
is homotopic to![]()
A continuous function
for all
exists such that![]()
Define![]()
Then
and![]()
are continuous, nH is continuous so
is a homotopy and
and
are homotopic.