Theorem
In the Euclidean space
there are some subsets that are not Borel sets.
Proof
Let
be a topological space and let B be the family of Borel sets in![]()
Then
The topological space
has a countable basis and the cardinal number of
is![]()
Hence![]()
Since card![]()
Hence there are sets in
that are not Borel sets.