Theorem
Letbe a countable set of second countable metric spaces.
The cartesian productis second countable.
Proof
Since eachis second countable, a countable basis
exists for the topology on
for each
A basis for
is the cartesian product of the bases for the
We can write it as vector, each component of which is countable, so the vector itself is a countable quantity and
is second countable.