Theorem
Let
be a topological space and let
be a subspace. A set
is closed in
if and only if
where
is closed in![]()
Proof
Suppose
is closed in
then
where
is open in![]()
Then
where![]()
Hence![]()
Since![]()
is closed in![]()
Suppose
where
is closed in![]()
Then![]()
where
is open in
and
is open in
Hence
is closed in![]()