Theorem
Ifis a set (open or closed) and
is the boundary of the set then the closure of
labelled
is equal to the union of
and the boundary of
labelled
More concisely,
Proof
Supposethen
hence
Since
and
Suppose now thatIf
then good. Suppose then that
but
Each neighbourhood of
intersects
at a point distinct from
hence
therefore
Hence