Theorem
1. If
is a set and
is the closure of
then![]()
2.![]()
3.![]()
4.![]()
Proof
Let
where
is closed for each
The intersection of any collection of closed sets is closed, Cl(A) is a closed set. A is closed if and only if Cl(A)=A so Cl(Cl(A))=Cl(A).
Let
and
where
for each
and
for each
Since
each
contains
hence![]()
is closed.
and
so
(1)
On the other hand
is closed and
subset
hence
(2)
From (1) and (2)![]()
is closed hence![]()