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The wavefunction must satisfy certain mathematical conditionsbecause of this probabilistic interpretation. For the case of asingle particle, the probability of finding it somewhere is 1, sothat we have the normalization condition
It is customary to normalize particle wavefunctions to 1. Thewavefunction must be single-valued, continuous, and finite.
Postulate 2. To every observable in classical mechanics therecorresponds a linear, Hermitian operator in quantum mechanics.If we require that the expectation value of an operator
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This postulate captures the central point of quantummechanics--the values of dynamical variables can be quantized(although it is still possible to have a continuum of eigenvalues inthe case of unbound states). If the system is in an eigenstateofwitheigenvalue
thenany measurement of the quantity
willyield
Although measurements must always yield an eigenvalue, the statedoes not have to be an eigenstate of initially.An arbitrary state can be expanded in the complete set ofeigenvectors of
as
where the summation may be infinite. In this case we only knowthat the measurement ofwillyield one of the eigenvalues of
butwe don't know which one. However, we do know the probability thateigenvalue
willoccur--it is the absolute value squared of the coefficient,
A consequence is that, after measurement ofyieldssome eigenvalue
thewavefunction immediately ``collapses'' into the correspondingeigenstate
orin the case that
isdegenerate, so has more than one corresponding eigenvector,then
becomesthe projection of
ontothe degenerate subspace). Thus, measurement affects the state of thesystem. This fact is used in many elaborate experimental tests ofquantum mechanics.
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The Pauli exclusion principle is a direct result ofthis antisymmetry principle.