The simplest first order differential equation is of the form
(1). We can solve this equation by assuming a solution of the form
so that
Substituting these into the differential equation (1) gives![]()
since that would mean the solution is trivial (and does not satisfy any boundary conditions) and
so![]()
If
when
then![]()
If instead we have a first order differential equation with vectors, say
(2) with
when
we can still assume a solution of the form
but now
is also a vector
which we have to find given the initial conditions.
If
then
Substituting into the differential equation (2) gives![]()
As before, we can factorise with
to give![]()
Again as before
and
so
hence
(3)
To find
use the initial conditions
when
hence
so![]()
We can write this solution in vector form as![]()
More complicated equations may include constant terms added. For example
(4)
with
when![]()
We find the solution in two parts. The first part will be the solution to
This is (3) above. The second part is any solution to (4). We can see that if
is a constant then
so put
into (4) then![]()
The general solution is the sum of
and
so
We can find
using the initial conditions
when![]()
![]()
Hence![]()
We can write this as![]()