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We can solve any quadratic inequality by completing the square.
Example: Solve  
\[x^2-6x-16 \lt 0\]

Completing the square gives  
\[(x-3)^2 -(-3)^2-16 = (x-3)^2-25 \lt 0\]

Hence  
\[(x-3)^2 \lt 25\]
.
Taking the square root gives  
\[-5 \lt x-3 \lt 5\]
.
Now add 3 to give  
\[-2 \lt x \lt 8\]
.