Sums, products, differences and quotients of sequences converge in the obvious way.
Theorem
If converges to
converges to and
and converges to
converges to then
then converges to
converges to
Proof: Choose There is a positive integer
There is a positive integer such that if
such that if then
then and a positive integer
and a positive integer such that if
such that if then
then Let
Let then if
then if
 and
and  then
then
Hence converges to
converges to
 
Theorem
If converges to
converges to and
and converges to
converges to then
then converges to
converges to
Proof: Choose
Choose Since
Since there is a positive integer
there is a positive integer such that if
such that if then
then a positive integer
a positive integer such that if
such that if then
then and a positive integer
and a positive integer such that if
such that if then
then Let
Let then if
then if

 and
and 
 so take
so take then
then


 
Theorem
If converges to
converges to and
and converges to
converges to then
then converges to
converges to
Proof: Choose There is a positive integer
There is a positive integer such that if
such that if then
then and a positive integer
and a positive integer such that if
such that if then
then Let
Let then if
then if
 and
and  then
then
Hence converges to
converges to
Theorem
If converges to
converges to and
and converges to
converges to then
then converges to
converges to
Proof: Choose Since
Since converges, it is bounded so there exists
converges, it is bounded so there exists such that
such that for all
for all Let
Let There is a positive integer
There is a positive integer such that if
such that if then
then and a positive integer
and a positive integer such that if
such that if then
then Let
Let then if
then if
 and
and  then
then
Hence converges to
converges to