The Weierstrass M – Test gives an often quick and easy method of determining whether of not a series is uniformly convergent.
Theorem (Weierstrass M – Test)
Suppose
is a sequence of functions defined on a set E and
is a sequence of nonnegative real numbers such that
for all
If
converges then so does
and this also converges uniformly on![]()
Proof: Choose
Since
converges, there is a real number
such that for positive integers
we have
Then for all positive integers
and![]()
implies that
for all x in E, hence
converges uniformly on E.
Example: Show that
converges uniformly on![]()
so take![]()
![]()
The last expression is a geometric series with first term
and common ratio![]()
Since
the geometric series converges, so by comparison
converges in this example and
converges uniformly on![]()
Example: Show that
where
odd and
even converges uniformly on![]()
on
so take![]()
![]()
This is a geometric series with first term
and common ratio
Since
this series converges so
converges uniformly.