Theorem
The following statements are equivalent:
-
is compact. -
For every family
of closed subsets of
contains a finite subclass
such that
Proof
Suppose
then from De Morgans's Laws,![]()
is an open cover of
because all the
are closed.
Since
is compact a finite subcover
exists.
Again from De Morgans' Laws,![]()
Conversely, let
be an open cover of
so that
where each
is open in![]()
From De Morgans' Laws,![]()
All the
are closed and have empty intersection. A subclass of
exists such that![]()
Again using De Morgan's Laws,
and
is compact.