Theorem
A subspace
of a first countable set
is also first countable.
Proof
Let
be a first countable space and let
be a subspace.
Let
By hypothesis
is first countable, so a countable basis
in
exists.
For each
define![]()
Then each
is open in
and form a
local subbase at![]()
The set
is countable. Hence
is a first countable space.