Theorem
A spaceis regular if and only if for everyand every open neighbourhoodof contains a closed neighbourhoodof with
Proof
Supposeis regular and letbe a point ofLetbe an open neighbourhood ofthenis closed and
Hence open setsandexist such that
Sincewe haveSincewe have
Hence
Now supposeandis an open subset ofwithAn open neighbourhoodofexists with
Letand letbe any closed subset ofwithis an open neighbourhood ofthen an open setexists withand
is open and
so
Henceandare the required open sets andis regular.