Theorem
Every complete metric space
is second category.
Proof
A topological space
is said to be first category if
is the countable union of nowhere dense subsets of
All other topological spaces are said to be second category.
Let
be first category. By definition then,
where each
is a nowhere dense subset of![]()
Since
is nowhere dense in
there exists
and
such that
so![]()
is open and
is nowhere dense in
so there exist
such that
and![]()
Set
then
and![]()
In this way we obtain a nested sequence of of closed sets![]()
such that fo
and![]()
Hence
and
exists such that![]()
Also
for every
and![]()
Thus
is second category.